Any given element of the vector will be the logical value TRUE if the element at the corresponding position in data$Age is a number divisible by 5 between 5 and 85 (this is what %in% seq(5,85,5) does) AND the value of the element at that position in data$Sex is equal to 1 (this is what data$Sex=1 does.) The & operator serves to evaluate that both cases are TRUE. When the active class is imbalanced in the markup in BS5, the. Im being vague because the active class can appear as either li.nav-item.active or. In your example: data$Age %in% seq(5,85,5) & data$Sex=1 will return a vector with the same length as data$Age. Fixes 411 This is a minimal fix for the behavior described in 411. remainder after division) + - > %in%(a,b). Normally expressed infix operators in base R include %o% (outer product) and %% (modulo, i.e. Infix functions operate on the expressions to the left and right of themselves, rather than on arguments provided inside (). typing ?%in% in the console will give you the documentation for the %in% function. It's hard for me to type a backtick because this comments forum turns it into a code block but on a standard keyboard the backtick is the key above the left tab.

to look up the documentation for it, by putting the function call in backticks.

You can force the R parser to evaluate an infix function 'normally', i.e. Any operator surrounded by % is called an 'infix function'.

R studio